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Title : Pagination
Categories : PHP, Databases, MySQL Click here to Update Your Picture
leaping langoor
Date : Oct 28th 2005
Grade : 1 of 5 (graded 4 times)
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A simple search with pagination in MySQL:

** Author : leapinglangoor [ [email protected] ]
** desc:
** This code will search trough records in an SQL database and
** display the amount of results that you want. If there are
** more records than the maximum amount it will display
** 'Previous 1,2,3,4,etc. 'Next'.
** Note : This code seems long and complicated but if you read
** the comment carefully you'll see its actually very easy!
** Also Edit the first line of the code to match your conditions

// PLease state your condition which will appear after WHERE in the sql
$cond = "`field` LIKE $foo";      // Or something

// Connect to SQL database
$global_db = mysql_connect('localhost', 'username', 'password');
mysql_select_db('databasename', $global_db);
// First query to find out how many reco
//     rds we have
$query = "SELECT Fields FROM Table WHERE $cond";

$result = mysql_query($query);
// Number of records found
$num_record = mysql_num_rows($result);
// Number of records you want to display
//     per page
$display = 25;
// Message when no records found
$XX = 'Sorry, no results were found!';
// If there are no records then startrow
//     is 0
if (empty($startrow)) {
// Actual query, watch the end of the qu
//     ery, here's where we set the LIMIT per p
//     age
$query2 = "SELECT Fields FROM Tabel WHERE your conditions LIMIT $startrow, $display";
$result2 = mysql_query($query2);
Put the results in a table
print("<table border=0><tr>");
I want only 3 results (in this case pictures) on 1 line, therefore i need a counter
= 0;
// Fetch the results (Begin loop)
while(list($Fields) = mysql_fetch_array($result2)) {
    * If
we have one line of three, move to the next line
if ($counter == 3) {
Set the counter to zero
= 0;
// Display the results on the screen, th
    //     is is just an example, make your own tab
    //     el here
print("<td bgcolor=#004A80 width=200 height=200 align=center><font color=#FFFFFF>$Field1</font><br><a href=\"showdetail.php?ID=$id\"><img src=\"images/$Image\" border=0 width=170 height=170></a><br><font color=#FFFFFF>FL $PriceNlg   € $PriceEuro</font></td>");
Increase the counter with 1
= $counter + 1;
// End loop
// Calculate the previous results, only
//     print 'Previous' if startrow is not equa
//     l to zero
if ($startrow != 0) {
$prevrow = $startrow - $display;
"<a href=\"$PHP_SELF?startrow=$prevrow\">Previous</a> "); \\ Of cource here you can send more
} variables seperated by &
// Calculate the total number of pages
$pages = intval($num_record / $display);
// $pages now contains number of pages n
//     eeded unless there are left over from di
//     vision
if ($num_record % $display) {
// has left over from division, so add one page
// Print the next pages, first check if
//     there are more pages then 1
if ($pages > 1) {
    for (
$i=1; $i <= $pages; $i++) { // Begin loop
$nextrow = $display * ($i - 1);
"<a href=\"$PHP_SELF?startrow=$nextrow\">$i</a>  "); \\ Also here you can send more
} variables seperatd by &
//End loop
// Check if we are at the last page, if
//     so, dont print 'Next'
if (!(($startrow / $display) == $pages) && $pages != 1) {
// not the last page so print 'Next'
$nextrow = $startrow + $display;
"<a href=\"$PHP_SELF?startrow=$nextrow\">Next</a>");
// If there are no results at all
if ($num_record < 1) {
"<table border=0 width=795><tr><td>$XX</td></tr></table>");

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