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Title : Find the number of days between today and a date in the future or in the past.
Categories : PHP, Date Time, Beginner Guides, Data Validation Click here to Update Your Picture
Aris Karidis
Date : Jan 31st 2006
Grade : 1 of 5 (graded 1 times)
Viewed : 5437
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<?php
/**
* Find the number of days between today and a date in the future or in the past.
*
* @param int $year
* @param int $month
* @param int $day
* @param int $accuracy
*/
function numberOfDays($year, $month, $day, $accuracy = 0)
{
   
# Check for valid parameters #
   
if (!is_int($day) || $day < 1 || $day > 31)
    {
       
printf('Wrong parameter for $day. It must be an integer between 1 and 31.');
        exit();
    }
   
    if (!
is_int($month) || $month < 1 || $month > 12)
    {
       
printf('Wrong parameter for $month. It must be an integer between 1 and 12.');
        exit();
    }
   
    if (!
is_int($year) || $year < 0)
    {
       
printf('Wrong parameter for $year. It must be a positive integer.');
        exit();
    }
   
    if (!
checkdate($month, $day, $year))
    {
       
printf('Invalid date.');
        exit();
    }
   
    if (
$accuracy !== 0 && $accuracy !== 1)
    {
       
printf('Wrong parameter for $accuracy. It must be either 1 or 0.');
        exit();
    }
   
   
$now = time();
   
$today = date('d-m-Y', $now);
   
$result = (mktime(0, 0, 0, $month, $day, $year) - $now) / 86400;
   
    if (
$accuracy === 1)
    {
        echo
'The exact number of days between '.$today.' and '.$day.'-'.$month.'-'.$year.' are '.$result;
    }
    else
    {
        echo
'The number of days between '.$today.' and '.$day.'-'.$month.'-'.$year.' are '.(int)$result;
    }
}
?>

<html>
<head>
</head>
<body>
    <?php
       
echo numberOfDays(2006, 12, 31);
        echo
'<br>';
        echo
numberOfDays(2005, 12, 31, 1);
        echo
'<br>';
        echo
numberOfDays(2006, 1, 31);
        echo
'<br>';
        echo
numberOfDays(2005, 12, 31);
   
?>
</body>
</html>



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