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Title : Find the day of the week for any given year/month/day.
Categories : PHP, Date Time, Data Validation, Algorithms, Beginner Guides Click here to Update Your Picture
Aris Karidis
Date : Jan 19th 2006
Grade : 2 of 5 (graded 3 times)
Viewed : 13316
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<?php
/**
* Find the day of the week for any given year/month/day.
* $calendarSystem specifies the calendar system
* 0 = Julian calendar
* 1 = Gregorian calendar
*
* @param int $day
* @param int $month
* @param int $year
* @param int $calendarSystem
* @return int
*/
function getDayOfWeek($day, $month, $year, $calendarSystem = 1)
{
   
# Check for valid parameters #
   
if (!is_int($day) || $day < 1 || $day > 31)
    {
       
printf('Wrong parameter for $day. It must be an integer between 1 and 31.');
        exit();
    }
       
    if (!
is_int($month) || $month < 1 || $month > 12)
    {
       
printf('Wrong parameter for $month. It must be an integer between 1 and 12.');
        exit();
    }
       
    if (!
is_int($year) || $year < 0)
    {
       
printf('Wrong parameter for $year. It must be a positive integer.');
        exit();
    }
       
    if (!
checkdate($month, $day, $year))
    {
       
printf('Invalid date.');
        exit();
    }
       
   
# Algorithm #       
   
if ($month < 3)
    {
       
$month = $month + 12;
       
$year = $year - 1;
    }
       
    return (
$day + (2 * $month) + (int) (6 * ($month + 1) / 10) + $year + (int) ($year / 4) - (int) ($year / 100) + (int) ($year / 400) + $calendarSystem) % 7;
}
?>



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